Uses of Interface
no.digipost.tuple.Hextuple

Packages that use Hextuple
Package
Description
no.digipost.tuple
 

  • Uses of Hextuple in no.digipost.tuple

    Methods in no.digipost.tuple that return Hextuple
    Modifier and Type
    Method
    Description
    Hextuple<T1,T2,T3,T4,T5,T6>
    Hextuple.asHextuple()
     
    Hextuple<T1,T2,T3,T4,T5,T6>
    ViewableAsHextuple.asHextuple()
     
    static <T1, T2, T3, T4, T5, T6>
    Hextuple<T1,T2,T3,T4,T5,T6>
    Hextuple.flatten(Tuple<Tuple<Tuple<Tuple<Tuple<T1,T2>,T3>,T4>,T5>,T6> nestedTuple)
     
    <S1, S2, S3, S4, S5, S6>
    Hextuple<S1,S2,S3,S4,S5,S6>
    Hextuple.map(Function<? super T1,? extends S1> firstMapper, Function<? super T2,? extends S2> secondMapper, Function<? super T3,? extends S3> thirdMapper, Function<? super T4,? extends S4> fourthMapper, Function<? super T5,? extends S5> fifthMapper, Function<? super T6,? extends S6> sixthMapper)
    Create a new hextuple by applying a function to each element, and putting the results into a new hextuple.
    <S5> Hextuple<T1,T2,T3,T4,S5,T6>
    Hextuple.mapFifth(Function<? super T5,? extends S5> mapper)
    Create a new hextuple by applying a function to the fifth element, and putting the result as the fifth element of the new hextuple.
    <S1> Hextuple<S1,T2,T3,T4,T5,T6>
    Hextuple.mapFirst(Function<? super T1,? extends S1> mapper)
    Create a new hextuple by applying a function to the first element, and putting the result as the first element of the new hextuple.
    <S4> Hextuple<T1,T2,T3,S4,T5,T6>
    Hextuple.mapFourth(Function<? super T4,? extends S4> mapper)
    Create a new hextuple by applying a function to the fourth element, and putting the result as the fourth element of the new hextuple.
    <S2> Hextuple<T1,S2,T3,T4,T5,T6>
    Hextuple.mapSecond(Function<? super T2,? extends S2> mapper)
    Create a new hextuple by applying a function to the second element, and putting the result as the second element of the new hextuple.
    <S6> Hextuple<T1,T2,T3,T4,T5,S6>
    Hextuple.mapSixth(Function<? super T6,? extends S6> mapper)
    Create a new hextuple by applying a function to the sixth element, and putting the result as the sixth element of the new hextuple.
    <S3> Hextuple<T1,T2,S3,T4,T5,T6>
    Hextuple.mapThird(Function<? super T3,? extends S3> mapper)
    Create a new hextuple by applying a function to the third element, and putting the result as the third element of the new hextuple.
    static <T1, T2, T3, T4, T5, T6>
    Hextuple<T1,T2,T3,T4,T5,T6>
    Hextuple.of(T1 first, T2 second, T3 third, T4 fourth, T5 fifth, T6 sixth)