接口的使用
org.dromara.stream.core.lambda.function.SerArgsFunc

使用SerArgsFunc的程序包

程序包	说明
org.dromara.stream.core.lambda.function

org.dromara.stream.core.lambda.function中SerArgsFunc的使用

org.dromara.stream.core.lambda.function中SerArgsFunc的子接口

限定符和类型	接口和说明
interface	SerArgsUnOp<T> SerArgsUnOp

返回SerArgsFunc的org.dromara.stream.core.lambda.function中的方法

限定符和类型	方法和说明
default <V> SerArgsFunc<T,V>	SerArgsFunc.andThen(SerArgsFunc<? super R,? extends V> after) Returns a composed function that first applies this function to its input, and then applies the after function to the result.
default <V> SerArgsFunc<T,V>	SerArgsFunc.andThen(SerArgsFunc<? super R,? extends V> after) Returns a composed function that first applies this function to its input, and then applies the after function to the result.
default <V> SerArgsFunc<V,R>	SerArgsFunc.compose(SerArgsFunc<? super V,? extends T> before) Returns a composed function that first applies the before function to its input, and then applies this function to the result.
default <V> SerArgsFunc<V,R>	SerArgsFunc.compose(SerArgsFunc<? super V,? extends T> before) Returns a composed function that first applies the before function to its input, and then applies this function to the result.
static <T> SerArgsFunc<T,T>	SerArgsFunc.last() Returns a function that always returns its input argument.
static <T> SerArgsFunc<T,T>	SerArgsFunc.last() Returns a function that always returns its input argument.

参数类型为SerArgsFunc的org.dromara.stream.core.lambda.function中的方法

限定符和类型	方法和说明
default <V> SerArgsFunc<T,V>	SerArgsFunc.andThen(SerArgsFunc<? super R,? extends V> after) Returns a composed function that first applies this function to its input, and then applies the after function to the result.
default <V> SerArgsFunc<T,V>	SerArgsFunc.andThen(SerArgsFunc<? super R,? extends V> after) Returns a composed function that first applies this function to its input, and then applies the after function to the result.
default <V> SerArgsFunc<V,R>	SerArgsFunc.compose(SerArgsFunc<? super V,? extends T> before) Returns a composed function that first applies the before function to its input, and then applies this function to the result.
default <V> SerArgsFunc<V,R>	SerArgsFunc.compose(SerArgsFunc<? super V,? extends T> before) Returns a composed function that first applies the before function to its input, and then applies this function to the result.