public class LinearSolverToSparse<D extends Matrix> extends java.lang.Object implements LinearSolverSparse<D,D>
| Constructor and Description |
|---|
LinearSolverToSparse(LinearSolverDense<D> solver) |
| Modifier and Type | Method and Description |
|---|---|
<D1 extends DecompositionInterface> |
getDecomposition()
If a decomposition class was used internally then this will return that class.
|
boolean |
isStructureLocked()
Checks to see if the structure is locked.
|
boolean |
modifiesA()
Returns true if the passed in matrix to
LinearSolver.setA(Matrix)
is modified. |
boolean |
modifiesB()
Returns true if the passed in 'B' matrix to
LinearSolver.solve(Matrix, Matrix)
is modified. |
double |
quality()
Returns a very quick to compute measure of how singular the system is.
|
boolean |
setA(D A)
Specifies the A matrix in the linear equation.
|
void |
setStructureLocked(boolean locked)
Save results from structural analysis step.
|
void |
solve(D B,
D X)
Solves for X in the linear system, A*X=B.
|
void |
solveSparse(D B,
D X)
Solve against sparse matrices.
|
public LinearSolverToSparse(LinearSolverDense<D> solver)
public void solveSparse(D B, D X)
LinearSolverSparsesolveSparse in interface LinearSolverSparse<D extends Matrix,D extends Matrix>B - Input. Never modified.X - Output. Never modified.public void setStructureLocked(boolean locked)
LinearSolverSparseSave results from structural analysis step. This can reduce computations of a matrix with the exactly same non-zero pattern is decomposed in the future. If a matrix has yet to be processed then the structure of the next matrix is saved. If a matrix has already been processed then the structure of the most recently processed matrix will be saved.
setStructureLocked in interface LinearSolverSparse<D extends Matrix,D extends Matrix>public boolean isStructureLocked()
LinearSolverSparseisStructureLocked in interface LinearSolverSparse<D extends Matrix,D extends Matrix>public boolean setA(D A)
LinearSolver
Specifies the A matrix in the linear equation. A reference might be saved
and it might also be modified depending on the implementation. If it is modified
then LinearSolver.modifiesA() will return true.
If this value returns true that does not guarantee a valid solution was generated. This is because some decompositions don't detect singular matrices.
public double quality()
LinearSolverReturns a very quick to compute measure of how singular the system is. This measure will be invariant to the scale of the matrix and always be positive, with larger values indicating it is less singular. If not supported by the solver then the runtime exception IllegalArgumentException is thrown. This is NOT the matrix's condition.
How this function is implemented is not specified. One possible implementation is the following: In many decompositions a triangular matrix is extracted. The determinant of a triangular matrix is easily computed and once normalized to be scale invariant and its absolute value taken it will provide functionality described above.
public void solve(D B, D X)
LinearSolverSolves for X in the linear system, A*X=B.
In some implementations 'B' and 'X' can be the same instance of a variable. Call
LinearSolver.modifiesB() to determine if 'B' is modified.
public boolean modifiesA()
LinearSolverLinearSolver.setA(Matrix)
is modified.public boolean modifiesB()
LinearSolverLinearSolver.solve(Matrix, Matrix)
is modified.public <D1 extends DecompositionInterface> D1 getDecomposition()
LinearSolvergetDecomposition in interface LinearSolver<D extends Matrix,D extends Matrix>D1 - Decomposition type